Thursday, February 27, 2020

MGT599 MoD 5 Case Assign Essay Example | Topics and Well Written Essays - 1500 words

MGT599 MoD 5 Case Assign - Essay Example In this paper, efforts have been made to understand whether various organizational components complement the primary strategy of the company and consequently suitable recommendations has been provided. Kraft Foods is an American company that primarily operates in North America and Canada and is one of the largest consumer packaged goods companies in the United States (US). The company was started in 1903 but it was re-launched in 2012 with a culture of collaboration and innovation. The company has a total of thirty brands selling different food items such as cheese, toppings, beverages, dressings, snacks and spreads. According to the company, at least ten brands of the company generate about $500 million in sales. The company is growing steadily and presently has approximately 22500 employees operating in the US and Canada (Kraft Foods Group, 2014a; 2014b). In this paper, the strategic position of the company along with its organizational design, organizational culture, human resource management and strategic system will be discussed in an elaborate manner. The rationale behind this attempt is to understand the efficiency of the strategy of the company and mitigate issues that are acting as barrier to strategy implementation in the company. It was ascertained from various published reports of Kraft Foods that the company has undergone major changes in recent years such as collaboration with McDonalds and multiyear licensing agreement with Keurig Green Mountain. It is assumed that such major decisions also have a strong impact on a company’s strategy and performance (Kraft Foods Group, 2014c; 2014d). The paper will evaluate various reports and articles about the company, for the purpose of analyzing various strategic developments in the company in recent years. By means of in-depth study, it is expected that the pertaining strategic issue of the company will be recognized so that appropriate recommendations can

Tuesday, February 11, 2020

Loaded Spring Oscillator, Hooke's Law Assignment

Loaded Spring Oscillator, Hooke's Law - Assignment Example The motion involves attachment of simple harmonic oscillator to the spring with the other end on the wall or any other rigid support system. The oscillator’s motion is repetitive at constant frequency hence periodic (Serway & Jewett, 2006 p 54). When the oscillator passes through the equilibrium its velocity is maximum and zero when passing through the extreme positions in its oscillation. The acceleration experienced by the oscillator is proportional to the negative of its displacement from the midpoint of its motion. A system in equilibrium and at rest has no net force acting on the mass. Displacement of the mass from equilibrium causes a restoring elastic force which obeys Hooke’s to be exerted by the spring. The restoring force F, is found by multiplying the spring constant K, to the displacement from equilibrium x; F=-Kx. The extension of a spring is directly proportional to the load applied to it. This is referred to the Hooke’s Law of elasticity. The mater ial’s elastic limit is the maximum load that when exceeded the material will not be able to gain its original form. Therefore, Hooke’s Law do not apply on the material. The elastic limit varies among the materials. The materials following Hooke’s Law are known as Hookean materials or linear elastic materials. The materials regain their original form after deformation by the load on it. In the formulae used to determine Hooke’s Law a negative sign is added because the restoring force acts in an opposite direction of displacement. The formula was stated by Robert Hooke, a British physicist in the 17th century hence its name; Hooke’s Law. A spring of length L and cross-sectional area A, is considered a linear elastic material since its extension is linearly proportional to tits tensile stress by a constant. Materials such as rubber are regarded as non-linear or non-Hookean since the load is not proportional to the extension that occurs. The material c hanging least in extension when load is applied is regarded to have the greatest elastic force. Elasticity would be described in four ways; compression, flexure or bending, stretching or extension, torsion or twisting. Elasticity has two main kinds namely elasticity by volume and elasticity of form or shape. For example, elasticity of volume is mainly experienced by the gases and liquids. Elasticity of the two is considered perfect since when the load is applied or removed there is no lost of volume. Increase in temperature of the material would cause increased extension. Therefore, factors such as temperature are to be kept constant during the experiment to ensure the results are not misleading. The graph is expected to be as shown below: Figure 1 The springs are found to obey the Hooke’s law in combinations. Therefore the springs can be combined to cater for specific spring constant. For springs in series, the equivalent constant is equal to the following: 1/Keq = 1/K1 + 1/ K2 Therefore the equivalent spring constant is the reciprocal of the answer from above. If the springs are in parallel the equivalent spring constant is equal to the sum of the spring constants of the springs used. Keq = K1 + K2 The Apparatus The requirements for the experiment are the steel springs, tensile. Mass hangers with slotted masses, 100g. Retort stand base, rod, boss and clamp. Short length of stiff wire to combine springs in parallel. G-clamp if the retort stand base is